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JEE MAIN - Chemistry (2018 (Offline) - No. 9)

The major product of the following reaction is: JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English
JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Option 1
JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Option 2
JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Option 3
JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Option 4

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JEE Main 2018 (Offline) Chemistry - Haloalkanes and Haloarenes Question 147 English Explanation

OMe$$-$$ is a strong base and because of this E2 elimination will happen.

OMe$$-$$ will attack on H and make MeOH and leaving group Br will make NaBr then an ankene will be formed.

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